checkDateFormat($date){
if(preg_match(“/^([0-9]{2})\/([0-9]{2})\/([0-9]{4})$/”, $date)){
return true;
}else{
return false;
}
}

Thnaks….

function checkDateFormat(&$data){
preg_match_all(‘/(20\d{2})\/(0[1-9]|1[012])\/(0[1-9]|[12]\d|3[01])/’, $data, $matches, PREG_SET_ORDER);
$orderDates=array();
for ($i = 0; $i < count($matches); $i++) {
if(checkdate($matches[$i][2],$matches[$i][3],$matches[$i][1])){
$orderDates[]=strtotime($matches[$i][0]);
}
}
sort($orderDates);
$output=false;
for ($i=0;$i<sizeof($orderDates);$i++) {
if ($i!=0) {
$output.= ‘,’;
}
$output.= date(‘Y/m/d’,$orderDates[$i]);
}
if($output){
return $output;
} else {
return false;
}
}
$str = ’2008/02/29,2007/02/29,2004/07/07,2035/13/00,2005/04/25′; // 2008 was a leap year
echo checkDateFormat($str);

Thanks

in reply to the above poster, to make this function work you will need to slash out the slashes to make PHP recognise them… this will work…

if (preg_match (”/^([0-9]{2})\/([0-9]{2})\/([0-9]{4})$/”, $date, $parts))
{
if(checkdate($parts[2],$parts[1],$parts[3]))
return true;
else
return false;
}

Hope this helps!

if (preg_match (“/^([0-9]{2})/([0-9]{2})/([0-9]{4})$/”, $date, $parts))
{
if(checkdate($parts[2],$parts[1],$parts[3]))
return true;
else
return false;
}

but is gives an error Unknown modifier ‘(‘ in preg_match