Date format validation in PHP

• Sunday, May 11, 2008, 11:20
• php, tutorial
• 10 comments

function checkDateFormat($date)
{
  //match the format of the date
  if (preg_match ("/^([0-9]{4})-([0-9]{2})-([0-9]{2})$/", $date, $parts))
  {
    //check weather the date is valid of not
	if(checkdate($parts[2],$parts[3],$parts[1]))
	  return true;
	else
	 return false;
  }
  else
    return false;
}

echo checkDateFormat("2008-02-29"); //return true
echo checkDateFormat("2007-02-29"); //return false

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10 Comments on “Date format validation in PHP”

• 
  Suresh wrote on 12 May, 2008, 19:09

  I used checkdate() to validate date in format ‘YYYY-mm-dd’ . but i can’t able to get the expect result . Now i am using Javascript to validate date.
• 
  Roshan wrote on 13 May, 2008, 10:55

  You can’t rely on the validation of javascript, as it can be bypassed by disabling javascript in browser and that function was working perfectly for various supplied data……can you please post the dates from which you’ve got bad or wrong result..
• 
  Anand Acharya wrote on 25 November, 2008, 5:35

  how to validate date in (dd/mm/yyyy) format ?
  i have tried your function with

  if (preg_match (“/^([0-9]{2})/([0-9]{2})/([0-9]{4})$/”, $date, $parts))
  {
  if(checkdate($parts[2],$parts[1],$parts[3]))
  return true;
  else
  return false;
  }

  but is gives an error Unknown modifier ‘(‘ in preg_match
• 
  ben wrote on 25 February, 2009, 17:13

  if (preg_match (”/^([0-9]{2})/([0-9]{2})/([0-9]{4})$/”, $date, $parts))
  {
  if(checkdate($parts[2],$parts[1],$parts[3]))
  return true;
  else
  return false;
  }

  in reply to the above poster, to make this function work you will need to slash out the slashes to make PHP recognise them… this will work…

  if (preg_match (”/^([0-9]{2})\/([0-9]{2})\/([0-9]{4})$/”, $date, $parts))
  {
  if(checkdate($parts[2],$parts[1],$parts[3]))
  return true;
  else
  return false;
  }

  Hope this helps!
• 
  Bogdan wrote on 5 May, 2009, 18:10

  Can anyoane help me to validate a date and time field? The format is yyyy-mm-dd HH:mm:ss (ex: 2009-05-18 20:59:50)

  Thanks
• 
  Joe wrote on 22 May, 2009, 23:02

  Here is a function if you have a string of dates that need to be validated. I also need to pick off the last date, thats why it is sorted. This is a pretty strict function obviously you can tone it down to your needs, most could probably do without checkdate since most date errors will be caught in the preg, and of course you probably don’t need a sort.

  function checkDateFormat(&$data){
  preg_match_all(‘/(20\d{2})\/(0[1-9]|1[012])\/(0[1-9]|[12]\d|3[01])/’, $data, $matches, PREG_SET_ORDER);
  $orderDates=array();
  for ($i = 0; $i < count($matches); $i++) {
  if(checkdate($matches[$i][2],$matches[$i][3],$matches[$i][1])){
  $orderDates[]=strtotime($matches[$i][0]);
  }
  }
  sort($orderDates);
  $output=false;
  for ($i=0;$i<sizeof($orderDates);$i++) {
  if ($i!=0) {
  $output.= ‘,’;
  }
  $output.= date(‘Y/m/d’,$orderDates[$i]);
  }
  if($output){
  return $output;
  } else {
  return false;
  }
  }
  $str = ’2008/02/29,2007/02/29,2004/07/07,2035/13/00,2005/04/25′; // 2008 was a leap year
  echo checkDateFormat($str);
• 
  Joe wrote on 22 May, 2009, 23:07

  ps the above preg only accept years 2000 – 2099, you need to adjust this for your preferences
• 
  Bogdan wrote on 24 May, 2009, 10:20

  Thanks
• 
  pooja wrote on 18 May, 2010, 9:14

  hello.. i am trying to fetch datetime from a text…. can any one help me how can i do this using regular expression preg_match????

  Thnaks….
• 
  decade wrote on 24 June, 2011, 9:48

  damn this i use your preg_match and it give an error so i modify it into more simple code :

  checkDateFormat($date){
  if(preg_match(“/^([0-9]{2})\/([0-9]{2})\/([0-9]{4})$/”, $date)){
  return true;
  }else{
  return false;
  }
  }

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