Comments on: Date or Time Comparison in PHP

By: Tapan Kumar Thapa

Tapan Kumar Thapa — Fri, 18 Feb 2011 09:14:02 +0000

Thanks it works…:-)

Regards
Tapan Thapa
India

By: Muneeb

Muneeb — Wed, 25 Aug 2010 09:29:13 +0000

hi
guys you can also use mysql for this purpose
the query SELECT TIMEDIFF(‘$Date1′ , ‘$Date2′) wil do the job
here is the link
http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_timediff
also there are many other time and date manipulation functions in mysql you might want to check out on the link given above

By: Mayor sipayung

Mayor sipayung — Fri, 25 Jun 2010 16:31:37 +0000

Thank you for the script

By: Sheetal

Sheetal — Thu, 29 Apr 2010 17:42:09 +0000

Could you please tell me either time is in 24 hr or in 12 hrs format?

By: Rebecca

Rebecca — Fri, 17 Jul 2009 05:48:46 +0000

Thank you for the script. Unlike make scripts on the net, it compares the date, the month and the year. Its logically correct.

By: IMF

IMF — Tue, 09 Jun 2009 16:59:19 +0000

Looks good, I shall try it.

By: cc

cc — Tue, 13 Jan 2009 02:11:33 +0000

i think u dont have to do $start-$end just do $start>$end

By: Mann

Mann — Mon, 06 Oct 2008 12:14:10 +0000

StartDate:10/08/2008

Enddate:06/10/2008
but the result is not correct

By: Roshan

Roshan — Sun, 18 May 2008 05:23:06 +0000

This function doesn’t support the UK datetime format..and that’s why you’re getting improper result…it’s beeter to have the date and time in “YYYY-MM-DD” format or “YYYY-MM-DD HH:MM:SS” format…

By: shels

shels — Sat, 17 May 2008 15:49:43 +0000

If first date is 17/05/2008 and second date is 18/04/2008
greaterDate($date1,$date2);
will display as 0. Meaning 17/05/2008 is less than 18/04/2008 which is wrong. It is comparing only the dates.

By: Roshan

Roshan — Mon, 31 Mar 2008 18:50:37 +0000

No problem at all man…
when i tried with
if(greaterDate(’2007-10-10 09:15:27′,’2007-10-10 11:17:37′))
echo “First parameter is greater”;
else
echo “Second parameter is greater”;

I got the result
“Second parameter is greater”

By: vipin

vipin — Mon, 31 Mar 2008 11:20:54 +0000

Hello,
I have observed that this function

if(greaterDate($date1,$date2))
echo “First parameter is greater”;
else
echo “Second parameter is greater”;

work well for below values

$date1=’2007-10-10 12:15:27?;
$date1=’2007-10-10 11:17:37?;

but NOT for

$date1=’2007-10-10 9:15:27?;
$date1=’2007-10-10 11:17:37?;

Please reply.

By: Anti Veeranna

Anti Veeranna — Sun, 30 Dec 2007 17:45:00 +0000

damn, I don’t get it

I found this – http://bugs.php.net/bug.php?id=40691

The sample code there gives expected response to me e.g. DateTime Equal? false

And I’m on php 5.2.4

By: Anti Veeranna

Anti Veeranna — Sun, 30 Dec 2007 17:42:00 +0000

Ok, I take it back.

For some weird reason the code works. I get correct results when playing with the values, but this seems to be a simple side effect, there is nothing built into the datetime class to do that kind of comparisions, it is just a simple object instance comparision.

By: Anti Veeranna

Anti Veeranna — Sun, 30 Dec 2007 17:30:00 +0000

No you don't. Try this:

$date1 = new Datetime('2007-11-10 12:15:27');
$date2 = new Datetime('2007-10-10 12:15:27');
$date3 = new Datetime('2007-10-10 11:15:27');
$date4 = new Datetime('2007-10-10 12:15:27');

if ($date2 > $date1) {
print "date2 is later than date1";
} else {
print "date1 is later than date2";
}

print "\n";

if ($date3 > $date4) {
print "date3 is later than date4";
} else {
print "date4 is later than date3";
}

print "\n";

[~]> php date.php
date1 is later than date2
date4 is later than date3
[~]> php -v
PHP 5.2.4 (cli) (built: Dec 16 2007 23:51:11)